J
JD
y_p_w said:Not necessarily. Suppose I have no knowledge of: the car in question,
what speed it's currently travelling, or what rev rate it's running at.
If you tell me the engine is outputting 150 HP at a given instant,
it's still trasferring energy to the car at the rate of 111.9
kilijoules/sec, regardless of engine speed. It could be at 2000/3000/
4000/10,000/100,000/etc RPM, and the rate at which energy is added to
increase speed and/or offset parasitic losses would be the same.
That's what power is - the rate that energy is made available in one
form or another.
I'll keep on saying that knowing torque at the crankshaft, devoid of
knowing other factors (rev rate), will not tell how much energy is
being transferred from the engine to the rest of the car. Knowing
the power output at the crankshaft, devoid of knowing other factors,
does indicate the rate of energy being transferred to the rest of the
car.
Who cares? My point, in the original post is that HP is derived from torque
at a specific RPM. The engine rotates. It applies force by rotating.
Therefore, everything from the engine is dervived from its torque at a
specific RPM. If I know the torque and the RPM, I can derive its energy
output; whether in HP or KW; but I can derive its power. If I know its
maximum power, I still need to know its RPM to dervive its torque, or its
potential. Either way, power, gives no indication as to the performance of
the car unless you know a whole lot of other things.
I have a 300 HP car with 300 lb-ft of torque at its peaks. It easily smokes
my friend's 73 Dodge producing 342 HP (at the wheels) with 320 some-odd
lb-ft at the peaks. Why? Because my car is lighter, geared better, and is
AWD. HP alone will not give an indication as to the car's performance.